LeetCode 2185. Counting Words With a Given Prefix

Question

You are given an array of strings words and a string pref.

Return the number of strings in words that contain pref as a prefix.

A prefix of a string s is any leading contiguous substring of s.

 

Example 1:

Input: words = ["pay","attention","practice","attend"], pref = "at"
Output: 2
Explanation: The 2 strings that contain "at" as a prefix are: "attention" and "attend".

 

Example 2:

Input: words = ["leetcode","win","loops","success"], pref = "code"
Output: 0
Explanation: There are no strings that contain "code" as a prefix.

 

Constraints:

• 1 <= words.length <= 100
• 1 <= words[i].length, pref.length <= 100
• words[i] and pref consist of lowercase English letters.

 

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Solution

Python

class Solution:
    def prefixCount(self, words: List[str], pref: str) -> int:
        count = 0
        for word in words:
            if pref not in word:
                continue
            else:
                if word.index(pref) == 0:
                    count += 1
        return count

Java