LeetCode 1704. Determine if String Halves Are Alike

Question

You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.

Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.

Return true if a and b are alike. Otherwise, return false.

 

Example 1:

Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.

 

Example 2:

Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.

 

Constraints:

• 2 <= s.length <= 1000
• s.length is even.
• s consists of uppercase and lowercase letters.

 

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Solution

Python

class Solution:
    def halvesAreAlike(self, s: str) -> bool:
        count_a = count_b = 0
        VOWELS = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
        index_halves = int(len(s) / 2)
        a = s[:index_halves]
        b = s[index_halves:]
        for i in a:
            if i in VOWELS:
                count_a += 1
        for j in b:
            if j in VOWELS:
                count_b += 1
        
        if count_a == count_b:
            return True
        else:
            return False

Java